152x-16x^2=240

Solution for 152x-16x^2=240 equation:

152x-16x^2=240

We move all terms to the left:

152x-16x^2-(240)=0

a = -16; b = 152; c = -240;
Δ = b2-4ac
Δ = 1522-4·(-16)·(-240)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(152)-88}{2*-16}=\frac{-240}{-32}
=7+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(152)+88}{2*-16}=\frac{-64}{-32}
=+2
$